Calculations based on data analysis for this experiment: A student performed an experiment similar to this one using LiCl. Fill in the empty cells in the table. Freezing Point of Pure Water Volume pure water (mL) 19.9 Density of pure water (g/mL) 0.9982 Mass of pure water (8) Freezing point of pure water #1 (°C) Freezing point of pure water #2 (°C) Average freezing point of pure water (°C) Freezing point of Licl Solution 20.1 Volume water (mL) Density of water (g/mL) Mass of water (g) 0.9982 3.2760 Mass of weigh boat + LiCl (g) Mass emptied weigh boat (g) 2.9887 Mass of LiCl (8) 42.394 Molar mass LiCl (g/mol) Concentration of LiCl (m) Freezing point of solution #1 (°C) 0.8 Freezing point of Licl Solution Volume water (ml) 20.1 0.9982 3.2760 2.9887 = 42.394 Density of water (g/mL) Mass of water (g) Mass of weigh boat + LICI (g) Mass emptied weigh boat (g) Mass of LiCl (g) Molar mass Licl (g/mol) Concentration of LiCl (m) Freezing point of solution #1 (°C) Freezing point of solution #2 (°C) Average freezing point of solution (°C) Average freezing point depression (°C) Kf water (°C/m) Calculated Van't Hoff factor 0.8 1.86

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13-02-2020
Chemistry

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Calculations based on data analysis for this experiment: A student performed an experiment similar to this one using LiCl. Fill in the empty cells in the table. Freezing Point of Pure Water Volume pure water (mL) 19.9 Density of pure water (g/mL) 0.9982 Mass of pure water (8) Freezing point of pure water #1 (°C) Freezing point of pure water #2 (°C) Average freezing point of pure water (°C) Freezing point of Licl Solution 20.1 Volume water (mL) Density of water (g/mL) Mass of water (g) 0.9982 3.2760 Mass of weigh boat + LiCl (g) Mass emptied weigh boat (g) 2.9887 Mass of LiCl (8) 42.394 Molar mass LiCl (g/mol) Concentration of LiCl (m) Freezing point of solution #1 (°C) 0.8 Freezing point of Licl Solution Volume water (ml) 20.1 0.9982 3.2760 2.9887 = 42.394 Density of water (g/mL) Mass of water (g) Mass of weigh boat + LICI (g) Mass emptied weigh boat (g) Mass of LiCl (g) Molar mass Licl (g/mol) Concentration of LiCl (m) Freezing point of solution #1 (°C) Freezing point of solution #2 (°C) Average freezing point of solution (°C) Average freezing point depression (°C) Kf water (°C/m) Calculated Van't Hoff factor 0.8 1.86

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nwandukelechi nwandukelechi · Answer 1 · 2020-02-16T18:37:52+01:00

Explanation:

A.

Mass of pure water = density * volume

= 19.9 * 0.9982

= 19.86 g

Average freezing point = (T1 + T2)/2

= 4/2

= 2 °C

B.

Mass of water = density * volume

= 20.1 * 0.9982

= 20.06 g

Mass of LiCl = mass of weigh boat + LiCl - mass of weigh boat

= 3.2760 - 2.9887

= 0.2873 g.

Number of moles = mass/molar mass

= 0.2873/42.394

= 0.0068 mol.

Molality, m = number of moles of LiCl/mass of solvent

= 0.0068/0.01986

= 0.34 mol/kg.

Average freezing point of LiCl = (T1 + T2)/2

= 1.4/2

= 0.7 °C.

Using freezing point depression,

ΔTF = KF * b * i

where:

ΔTF / freezing-point depression = Temp.F(pure solvent) − Temp.F(solution).

KF = cryoscopic constant, which is dependent on the properties of the solvent, not the solute. For water, KF = 1.853 K·kg/mol.

b = molality

i = van 't Hoff factor

2 - 14 = 1853 * 0.34 * i

i = 0.019