Answer:
V2 = 370.22 mL
Explanation:
assuming ideal gas:
V1 = 490.0 mL = 0.490 L
T1 = - 35.0 °C ≅ 238 K
T2 = 42.0°C ≅ 315 K
⇒ V2 = ?
∴ assuming constant pressure, we can apply the Charles's law:
⇒ V1/T1 = V2/T2
⇒ V2 = V1T1/T2
⇒ V2 = ((0.490 L)(238 K))/(315 K)
⇒ V2 = 0.3702 L = 370.22 mL
