Answer:
a)[tex]\Delta P= 2666.66 Pa[/tex]
b)[tex]\Delta P= 3200 Pa[/tex]
Explanation:
Given that
Diameter ,d= 0.15 mm
We know that pressure difference is given as
[tex]\Delta P=\dfrac{4\sigma }{d}[/tex]
Now by putting the values
When surface tension 0.1 N/m :
The surface tension ,[tex]\sigma=0.1\ N/m[/tex]
[tex]\Delta P=\dfrac{4\times 0.1 }{0.15}\times 10^3\ Pa[/tex]
[tex]\Delta P= 2666.66 Pa[/tex]
When surface tension 0.12 N/m :
The surface tension ,[tex]\sigma=0.12\ N/m[/tex]
[tex]\Delta P=\dfrac{4\times 0.12 }{0.15}\times 10^3\ Pa[/tex]
[tex]\Delta P= 3200 Pa[/tex]
a)[tex]\Delta P= 2666.66 Pa[/tex]
b)[tex]\Delta P= 3200 Pa[/tex]
