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A 0.3480 g sample of potassium hydrogen phthalate is dissolved in 100.0 mL of water. If 32.07 mL of sodium hydroxide solution are required to reach the equivalence point, what is the molarity of the sodium hydroxide solution

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Answer:

Recall the following terms which is,

KHP is Potassium hydrogen phthalate

NaOH is Sodium Hydroxide

NaKP is molar mass

H20 is water

Explanation:

KHP + NaOH = NaKP + H2O

moles of KHP = 0.3480g / 204.22 g·mol−1 = .001704

these will react with the same number of moles of NaOH according to the equation  

these are in 0.03207 L of solution

The  molarity of the NaOH solution = 0.001704 mol / 0.03207 L = 0.0531 M

the water takes no part in the reaction and the quantity can be ignored

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