Incomplete question.The complete one is here
A runner taking part in the 200m dash must run around the end of a track that has a circular arc with a radius curvature of 30m. The runner starts the race at a constant speed. If she completes the 200m dash in 23s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track?
Answer:
[tex]a_c=2.523m/s^2[/tex]
Explanation:
Given data
[tex]L_{length}=200m\\r_{radius}=30m\\t_{time}=23s[/tex]
Required
Centripetal acceleration
Solution
According to the motions equation the velocity given by:
[tex]V_{velocity}=\frac{L_{length}}{t_{time}}\\V_{velocity}=\frac{200m}{23s}\\V_{velocity}=8.7m/s[/tex]
The centripetal acceleration is given by:
[tex]a_{c}=\frac{V_{velocity}^2}{r_{radius}}\\ a_c=\frac{(8.7m/s)^2}{30m}\\ a_c=2.523m/s^2[/tex]
