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A 5kg ‏ Of copper specific heat capacity =385j/kg C at 20 c is given 46200 j of energy what will be the final temperature

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rafaleo84

Answer:

T_f = 44 [C]

Explanation:

The following heat transfer equation is used to solve this type of problem.

Q = m*Cp*(T_f - Ti)

Q = 46200 [J]

Cp = 385 [J/kg*C]

m = 5 [kg]

Ti = 20 [C]

Now replacing:

46200 = 5*385*(T_f - 20)

46200 = 1925*T_f - 38500

84700 = 1925*T_f

T_f = 44 [C]

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