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How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33×10−21 n?

Respuesta :

akindelemf

Answer:

The number of excess electrons on each sphere is 759

Explanation:

Given that,

distance , d = 20 cm

                    = 0.20 m

let the number of electrons is n  

Electric force (F) = k × (n × e)² /d²

3.33 × [tex]10^{-21}[/tex] = 9 × [tex]10^{9}[/tex] × (n × 1.602 × [tex]10^{-19}[/tex])² /0.2²

solving for n

n = 759

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