Luke,kira and ali each served 2 thirds of their own cake. Each cake was the same size, but luke served 4 slices, kira served 6 slices, and ali served 8 slices. How is this possible? Enter your awnsers in the boxes to complete the solution

Respuesta :

Answer:

The whole slices of Luke,kira and Ali are 6, 9 and 12. So it is possible.

Step-by-step explanation:

Given:

Luke,kira and ali each served 2 thirds of their own cake. Each cake was the same size, but luke served 4 slices, kira served 6 slices, and Ali served 8 slices.

Now, to find how is this possible.

Let the whole slices of cake be [tex]x.[/tex]

Luke served  [tex]\frac{2}{3}[/tex]  of his cake which are 4 slices.

So, the whole slices of cake of Luke is:

[tex]\frac{2}{3} \ of\ x=4[/tex]

[tex]\frac{2}{3} \times x=4[/tex]

Multiplying both sides by 3 we get:

[tex]2\times x=12[/tex]

Dividing both sides by 2 we get:

[tex]x=6.[/tex]

Thus, whole slices of Luke's cake is 6.

Kira served [tex]\frac{2}{3}[/tex]  of her cake which are 6 slices.

So, the whole slices of Kira's cake is:

[tex]\frac{2}{3} \ of\ x=6[/tex]

[tex]\frac{2x}{3} =6[/tex]

Multiplying both sides by 3 we get:

[tex]2x=18[/tex]

Dividing both sides by 2 we get:

[tex]x=9[/tex].

Therefore, whole slices of KIra's cake is 9.

Now, Ali served [tex]\frac{2}{3}[/tex]  of her cake which are 8 slices.

So, the whole slices of Ali's cake is:

[tex]\frac{2}{3} \ of\ x=8[/tex]

[tex]\frac{2x}{3} =8[/tex]

Multiplying both sides by 3 we get:

[tex]2x=24[/tex]

Dividing both sides by 2 we get:

[tex]x=12.[/tex]

Hence, whole slices of Ali's cake is 12.

Now, as it is the whole slices of Luke,kira and Ali are 6, 9 and 12.

Thus, it is possible.

Therefore, the whole slices of Luke,kira and Ali are 6, 9 and 12. So it is possible.