Step-by-step explanation:
[tex] \frac{1}{3} p + \frac{1}{2} p + 7 = \frac{7}{6} p + 5 + 4 \\ \\ \therefore \: \frac{1}{3} p + \frac{1}{2} p - \frac{7}{6} p = 9 - 7 \\ \\ \bigg( \frac{1}{3} + \frac{1}{2} - \frac{7}{6} \bigg) p= 2 \\ \\ \therefore \: \bigg( \frac{2}{6} + \frac{3}{6} - \frac{7}{6} \bigg) p= 2 \\ \\ \therefore \: \bigg( \frac{2 + 3 - 7}{6} \bigg) p= 2 \\ \\ \therefore \: \bigg( \frac{5- 7}{6} \bigg) p= 2 \\ \\ \therefore \: \bigg( \frac{-2}{6} \bigg) p= 2 \\ \\ \therefore \:p = 2 \times \frac{6}{-2} \\ \\ \: \: \: \: \: \: \: \huge \red{ \boxed{ \therefore \:p = - 6}}[/tex]
