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A satellite of mass 4500 kg orbits the Earth in a circular orbit of radius of 7.2 × 106 m (this is above the Earth's atmosphere).The mass of the Earth is 6 × 1024 kg. What is the speed of the satellite?

Respuesta :

Answer:

7.457 * 10³ m/s

Explanation:

Parameters given:

Mass of earth, M = 6 * 10^24 kg

Radius of orbit, R = 7.2 * 10^6 m

Orbital velocity is given as:

v = √(GM/R)

Where G = gravitational constant

v = √(6.673 * 10^(-11) * 6 * 10^24)/(7.2 * 10^6)

v = √(5.561 * 10^7)

v = 7.457 * 10³ m/s

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