Oxides of virtually every element are known. Bromine, for example, forms several oxides when treated with ozone. Suppose you allow 1.650 g of bromine, Br2, to react with ozone and obtain 2.476 g of BrxOy. What is the formula of the product?

Respuesta :

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Answer:

EF = Br₂O₅

Explanation:

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Br to O.

Data:

     Mass of Br = 1.650 g

Mass of BrₓOy = 2.476 g

Calculations

1. Calculate the mass of O

Mass of O = 2.476 g - 1.650 g = 0.826 g

2. Calculate the moles of each element

[tex]\text{Moles of Br} = \text{1.650 g Br} \times \dfrac{\text{1 mol Br}}{\text{79.90 g Br}} = \text{0.020 65 mol Br}\\\text{Moles of O} = \text{0.826 g O} \times \dfrac{\text{1 mol O}}{\text{16.00 g O }} = \text{0.051 62 mol O}[/tex]

3. Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

Br:O = 0.020 65:0.051 62 = 1:2.500 ≈ 2:5

4. Write the empirical formula

EF = Br₂O₅

We can't calculate the molecular formula from the information given. It could be Br₂O₅, Br₄O₁₀, or any other multiple of Br₂O₅.