aarushij81 aarushij81
  • 12-03-2020
  • Mathematics
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Here is my problem x^2-12x=3

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konrad509
konrad509 konrad509
  • 12-03-2020

[tex]x^2-12x=3\\x^2-12x-3=0\\x^2-12x+36-39=0\\(x-6)^2=39\\x-6=-\sqrt{39} \vee x-6=\sqrt{39}\\x=6-\sqrt{39} \vee x=6+\sqrt{39}[/tex]

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