(A) 1.54
Explanation:
Given:
Heat, q = 435 J
Mass, m = 3.4 g
T₁ = 2°C
T₂ = 85°C
Specific heat, c = ?
We know:
q = mcΔT
where,
ΔT = T₂ - T₁
ΔT = (85°C - 2°C)
ΔT = 83°C
On substituting the value we get:
[tex]435 = 3.4 X c X (83)\\\\c = \frac{435}{3.4 X 83} \\\\c = 1.54 J/g^oC[/tex]
