Answer:
Step-by-step explanation:
The equation of a circle:
[tex](y-h)^2+(y-k)^2=r^2[/tex]
Where
[tex](h,\ k)[/tex] - center
[tex]r[/tex] - radius
We have the equation
[tex](x+2)^2+(y-4)^2=36\\\\\bigg(x-(-2)\bigg)^2+(y-4)^2=6^2[/tex]
Therefore
the center is (-2, 4)
the radius is 6