A circle has a radius of 6 inches. Find the area of a sector of this circle that is intercepted by a central angle measuring 30°. A. 2π. B. 3π. C. 6π. D. 12π

Respuesta :

The area of the sector of a circle is expressed in the formula: A = 1/2 r^2 * theta where theta is expressed in radians. In this case, we are given with r equal to 6 inches and theta equal to pi/3. Hence the area of the sector is equal to 18.85 cm2 or 6 pi cm2.

Answer:

Option B is correct

Step-by-step explanation:

Area(A) of sector  of the circle is given by:

[tex]A = \pi r^2 \cdot \frac{\theta}{360^{\circ}}[/tex]      ....[1]

As per the statement:

A circle has a radius of 6 inches.

⇒r = 6 inches

It is also given that a central angle is 30°

⇒[tex]\theta = 30^{\circ}[/tex]

Substitute the given values in [1] we have;

[tex]A = \pi \cdot 6^2 \cdot \frac{30^{\circ}}{360^{\circ}}[/tex]

⇒[tex]A = \pi \cdot 36 \cdot \frac{1}{12}[/tex]

⇒[tex]A = \pi \cdot 3[/tex]

Simplify:

[tex]A = 3 \pi[/tex] square inches

Therefore, the area of a sector of circle is, 3π inches