[tex] \frac{3}{4} (6x+19)=14 \\ 6x+19=(14) \frac{4}{3} = \frac{56}{3} \\ 3(6x+19)=56 \\ 18x+57=56 \\ 18x=56-57 \\ 18x=-1 \\ x= \frac{-1}{18} [/tex]
Substituting -1/18 to the original equation
[tex] \frac{3}{4} (6( \frac{-1}{18} )+9)=14 \\ 6.5 \neq 14[/tex]
No, it cannot be solved by the Division Property of Equality, as the property states that when both sides are divided by the same nonzero root, they are of equal value. As the result of x shows that the left hand side is not equal to that of the right, the equation does not fit with the property.
