Answer:
if you meant to put [tex](t-3)^{2}[/tex], then the answer is 7
Step-by-step explanation:
h=-2[tex](t-3)^{2}[/tex]+32
solve for t
0=-2[tex](t-3)^{2}[/tex]+32
subtract 32 from both sides
-32=-2[tex](t-3)^{2}[/tex]
divide both sides by -2
16=[tex](t-3)^{2}[/tex]
find suare root of 16
4= t-3
add 3 to both sides
7 = t
