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A skateboarder starts at 2.75 m/s and accelerates for 8.90 s over a distance of 16.7
m. What is his final velocity?

Respuesta :

MathPhys

Answer:

1.00 m/s

Explanation:

Given:

Δx = 16.7 m

v₀ = 2.75 m/s

t = 8.90 s

Find: v

Δx = ½ (v + v₀) t

16.7 m = ½ (v + 2.75 m/s) (8.90 s)

v = 1.00 m/s

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