Both the lines AD and BC will be parallel.
Sum of interior angles of a polygon is given by the expression,
Sum of interior angles of a polygon = (n - 2) × 180°
Here, n = number of the sides of the polygon
For a quadrilateral, n = 4
Therefore, sum of interior angles of the given quadrilateral = (4 - 2)×180°
= 360°
From the picture attached,
2x° + 3x° + x° + 90° = 360°
6x° = 360° - 90°
x° = [tex]\frac{270}{6}[/tex]
= 45°
Measure of ∠BAD = 2(45°)
= 90°
Since, m∠BAD = m∠CBA = 90°
Therefore, angles (∠BAD and ∠CBA) formed by the intersection of a transversal line AB and two lines AD and BC will be corresponding angles.
Hence, both the lines AD and BC will be parallel to each other.
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