Answer:
[tex]$\frac{1}{a^{12}b^8}$[/tex]
Step-by-step explanation:
Considering the expression:
[tex]$\left(\frac{a^{-3}}{b^2}\right)^4$[/tex]
[tex]$\frac{\left(a^{-3}\right)^4}{\left(b^2\right)^4}$[/tex]
Now state the property:
[tex]$a^{-1}=\frac{1}{a^n}, a\neq 0 $[/tex]
[tex]$\frac{\frac{1}{a^{12}}}{\left(b^2\right)^4}$[/tex]
[tex]$\frac{\frac{1}{a^{12}}}{b^8}$[/tex]
[tex]$\frac{1}{a^{12}b^8}$[/tex]
