mmmoje17
contestada

4. A spring is stretched 0.5 m from equilibrium. The force constant (k) of the
spring is 250 N/m. What is the potential energy of the spring?

Respuesta :

osikbro

Answer:

31.25

Explanation:

The formula for the potential energy of a spring is [tex]\frac{1}{2}kx^2[/tex], where x is the distance in meters the spring is stretched. Plugging in the numbers that you are given, you get [tex]\frac{1}{2}\cdot 250\cdot 0.25=31.25[/tex]. Hope this helps!

britney2908
31.25 hope this helps:)

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