Answer:
C.(–1.1, 1)
D.(–0.9, 2)
E.(2.2, 5)
Step-by-step explanation:
None of the points lie on the graph of function [tex]f(x) = |x| + 2[/tex]
The function is given as:
[tex]f(x) = |x| + 2[/tex]
Start by testing the input values.
When x = -5.5, we have:
[tex]f(-5.5) = |-5.5| + 2[/tex]
Remove absolute bracket
[tex]f(-5.5) = 5.5 + 2[/tex]
Add
[tex]f(-5.5) = 7.5[/tex]
(-5.5,4) is not a point on the graph, because [tex]f(-5.5) \ne 4[/tex]
When x = -3.8, we have:
[tex]f(-3.8) = |-3.8| + 2[/tex]
Remove absolute bracket
[tex]f(-3.8) = 3.8 + 2[/tex]
Add
[tex]f(-3.8) = 5.8[/tex]
(-3.8,-2) is not a point on the graph, because [tex]f(-3.8) \ne -2[/tex]
When x = -1.1, we have:
[tex]f(-1.1) = |-1.1| + 2[/tex]
Remove absolute bracket
[tex]f(-1.1) = 1.1 + 2[/tex]
Add
[tex]f(-1.1) = 3.1[/tex]
(-1.1,1) is not a point on the graph, because [tex]f(-1.1) \ne 1[/tex]
When x = -0.9, we have:
[tex]f(-0.9) = |-0.9| + 2[/tex]
Remove absolute bracket
[tex]f(-0.9) = 0.9 + 2[/tex]
Add
[tex]f(-0.9) = 2.9[/tex]
(-0.9,2) is not a point on the graph, because [tex]f(-0.9) \ne 2[/tex]
When x = 2.2, we have:
[tex]f(2.2) = |2.2| + 2[/tex]
Remove absolute bracket
[tex]f(2.2) = 2.2 + 2[/tex]
Add
[tex]f(2.2) = 4.2[/tex]
(2.2,5) is not a point on the graph, because [tex]f(2.2) \ne 5[/tex]
When x = 4.7, we have:
[tex]f(4.7) = |4.7| + 2[/tex]
Remove absolute bracket
[tex]f(4.7) = 4.7 + 2[/tex]
Add
[tex]f(4.7) = 6.7[/tex]
(4.7,6) is not a point on the graph, because [tex]f(4.7) \ne 6.7[/tex]
Hence, none of the points lie on the graph of function [tex]f(x) = |x| + 2[/tex]
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