Respuesta :
Answer:
Weight of cement = 10909.08 pounds
Weight of sand = 18008.64 lb
Weight of gravel = 28051.92 lb
Weight of water = 5454.54 lb
Explanation:
given data
length = 40 feet
width = 12 feet
thickness = 6 in = 0.5 feet
mix proportion = 1:2:3
specific gravity of cement = 3.15
specific gravity of sand = 2.60
specific gravity of gravel = 2.70
water to cement ratio = 0.50
solution
first we get here total volume that is
volume = length × width × thickness ...........1
volume = 40 × 12 × 0.5
volume = 240 feet³
and
now we get here dry volume of concrete that will be
Dry volume = wet volume × 1.54 .......................2
Dry volume = 240 × 1.54
Dry volume = 360 feet³
and
we have given air content entrained is = 7.5 %
so required volume will be as
required volume = Dry volume × ( 1 - 7% ) .............3
required volume = 360 × ( 1 - 7.5 % )
required volume = 333 feet³
and
total ratio is
total ratio = 1+ 2+ 3
total ratio = 6
so volume of sand cement and gravel will be
volume of cement = [tex]\frac{1}{6} \times 333[/tex]
volume of cement = 55.5 feet³
volume of sand = [tex]\frac{2}{6} \times 333[/tex]
volume of sand = 111 feet³
volume of gravel = [tex]\frac{3}{6} \times 333[/tex]
volume of gravel = 166.5 feet³
and
now we get here weight of sand cement and gravel as
weight = volume × specific gravity × density of water .............4
and now put here value and we get
Weight of cement = 55.5 × 3.15 × 62.4
Weight of cement = 10909.08 pounds
and
Weight of sand = 111 × 2.60 × 62.4
Weight of sand = 18008.64 lb
and
Weight of gravel = 166.5 × 2.7 × 62.4
Weight of gravel = 28051.92 lb
and
Weight of water = 0.5 of weight of cement
Weight of water = 0.5 × 1090.9.08
Weight of water = 5454.54 lb
