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11-06-2020
Chemistry

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Find the Empirical formula for 0.765g Cr, 0.235g O

Respuesta :

jeracoo jeracoo

11-06-2020

Answer:

CrO

Explanation:

0.765g Cr

0.235g O

O = 16g/mol

Cr = 52g/mol

O 2-

Cr 2+, 3+, 6+

0.765 + 0.235 = 1

so 76.5% Cr

23.5% O

76.5/52 = 1.47/1.47 = 1

23.5/16 = 1.47/1.47 = 1

CrO

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