Answer:
the volume of the gas at conditions of STP = 151.04998 ml
Explanation:
Data given:
V1 = 180 ml
T1 = 35°C or 273.15 + 35 = 308.15 K
P1 = 95.9 KPa
V2 =?
We know that at STP
P2 = 1 atm or 101.3 KPa
T2 = 273.15 K
At STP the pressure is 1 atm and the temperature is 273.15 K
applying Gas Law:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
putting the values in the equation of Gas Law:
[tex]V_2=\frac{P_1V_1T_2}{T_1P_2}[/tex]
V_2 =[tex]\frac{95.9\times180\times273.15}{308.15\times101.3}[/tex]
V2 = 151.04998
therefore, V2 = 151.04998 ml
Answer:
151 mL is the correct answer to the given question .
Explanation:
We know that
[tex]PV =n RT[/tex]
Where P =pressure ,V=volume and T=Temperature
Given
P=95.9 kPa.
V=[tex]180 * 10 ^{-3}[/tex]
R=25/3
T=273 + 35 =308k
Putting these value into the equation we get
[tex]95.9\ * 180\ *\ 10^{-3} \ =\ n * \frac{25}{3} * 308[/tex]
n=[tex]6.72 * 10^{-3}[/tex]
Now using the equation
[tex]n= \ \frac{V}{22.4}[/tex]
[tex]6.72 * 10^{-3} =\frac{V}{22.4}\\ V\ =\ 150.6mL[/tex]
This can be written as 151mL
