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12-06-2020
Physics

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If 320 J of work is done on a spring with a spring constant of 730 N/m, how far will it stretch?
a 0.58 m
b0.87 m
c0.94m
d0.61

Respuesta :

MathPhys MathPhys

12-06-2020

Answer:

0.94 m

Explanation:

EE = ½ kx²

320 J = ½ (730 N/m) x²

x = 0.94 m

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