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Given the directrix of y = 6 and focus of (0, 4), which is the equation of the parabola?
Oy=-1x2 +5
4
Oy=-=x2-5
Oy=
1x2 + 5
4
Oy
1x2-5
4

Given the directrix of y 6 and focus of 0 4 which is the equation of the parabola Oy1x2 5 4 Oyx25 Oy 1x2 5 4 Oy 1x25 4 class=

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sqdancefan

Answer:

  [tex]y=-\dfrac{1}{4}x^2+5[/tex]

Step-by-step explanation:

The directrix at y=6 is above the focus at y=4, so the parabola opens downward. This eliminates the last two choices.

The vertex is halfway between the focus and directrix, at y=5, eliminating the second choice. The first choice is appropriate.

  [tex]\boxed{y=-\dfrac{1}{4}x^2+5}[/tex]

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