Respuesta :
Answer: 8368 Joules
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed or released =?
c = specific heat capacity of water = [tex]4.184J/g^0C[/tex]
Initial temperature of water = [tex]T_i[/tex] = [tex]20^0C[/tex]
Final temperature of water = [tex]T_f[/tex] = [tex]60^0C[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(60-20)^0C=40^0C[/tex]
Putting in the values, we get:
[tex]Q=50.0g\times 4.184J/g^0C\times 40^0C=8368J[/tex]
Thus energy in Joules required is 8368.
