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What is an equation of the line that is perpendicular to y + 1 = -3(x - 5) and passes through the point (4, -6)?

What is an equation of the line that is perpendicular to y 1 3x 5 and passes through the point 4 6 class=

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HumanBein

Answer:

Option A.

Step-by-step explanation:

y + 1 = -3x + 15

y = -3x + 14

A line perpendicular would have a slope of 1/3.

y = 1/3x + c

-6 = 1/3 * 4 + c

4/3 + c = -6

c = -18/3 - 4/3

c = -22/3

So, we have y = 1/3x - 22/3.

y + 6 = 1/3(x - 4)

y + 6 = 1/3x - 4/3

y = 1/3x - 4/3 - 18/3

y = 1/3x - 22/3

So, the correct answer is Option A.

Hope this helps!

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