Answer:
Amadi is 86m far from Becky
Amadi is on the bearing of 78° .
Step-by-step explanation:
From the information given ,
let I represent Ikyume
A represent Amadi and B represent Becky
From the information in the diagrammatic expression shown below:
Using cosine rule;
i² = a² + b² - 2ab cos (I)
i² = 42² + 62² - 2(42×62) cos (110°)
i² = 1764 + 3844 - 5208 (- 0.342)
i² = 1764 + 3844 - ( - 1781.136)
i² = 1764 + 3844 + 1781.136
i² = 7389.136
i = [tex]\mathtt{\sqrt{7389.136}}[/tex]
i = 85.96
i [tex]\simeq[/tex] 86 m
Amadi is 86m far from Becky
From point I , 12° = 12° at point A (alternate angles)
In that quadrant = 90 - 12° = 78°
Therefore, Amadi is on the bearing of 78° .
