Answer:
Malcom's maximum speed = 200 km/h
Ravi's maximum speed = 320 km/h
Step-by-step explanation:
Let m = Malcom's maximum speed
Let r = Ravi's maximum speed
Average of their maximum speed would be represented as [tex] \frac{m + r}{2} = 260 [/tex]
[tex] m + r = 520 [/tex].
Make m the subject of the formula by subtracting r from both sides:
[tex] m = 520 - r [/tex]. Let this be equation 1.
Given that Malcom's speed (m), when doubled is 80 km/h more than that of Ravi (r). This can be expressed as: [tex] 2m = r + 80 [/tex]. This is equation 2.
Plug in (520 - r) into equation 2 to replace m:
[tex] 2(520 - r) = r + 80 [/tex]
[tex] 1040 - 2r = r + 80 [/tex]
Solve for r. Subtract 1040 from both sides:
[tex] 1040 - 2r - 1040 = r + 80 - 1040 [/tex]
[tex] - 2r = r - 960 [/tex]
Subtract r from both sides
[tex] - 2r - r = r - 960 - r [/tex]
[tex] - 3r = - 960 [/tex]
Divide both sides by -3
[tex] \frac{-3r}{-3} = \frac{-960}{-3} [/tex]
[tex] r = 320 [/tex]
To find m, plug in the value of r into equation 1.
[tex] m = 520 - r [/tex]. =>Equation 1
[tex] m = 520 - 320 [/tex]
[tex] m = 200 [/tex].
Malcom's maximum speed = m = 200 km/h
Ravi's maximum speed = r = 320 km/h
