Answer:
B) 24
D) 48
Step-by-step explanation:
Given:
Two fractions
[tex]\dfrac{1}6 \\and\\\dfrac{3}8[/tex]
To find:
Number that can be chosen as Common denominator such that numerator is also a whole number ?
Solution:
Common denominator for two fractions [tex]\frac{p}{q}[/tex] and [tex]\frac{r}{s}[/tex] is chosen as LCM or multiple of LCM of (q, s).
OR
Common denominator for two fractions is chosen as the Least Common Multiple or multiple of LCM of denominators of the two fractions.
The denominators of the given fractions are 6 and 8.
Let us factorize and try to find the LCM of 6 and 8.
[tex]6 = \underline2 \times 3\\8 = \underline2 \times 2\times 2[/tex]
Common part of the denominators (as underlined) will be taken only once.
So, [tex]LCM = 2 \times 3 \times 2 \times 2 =24[/tex]
Multiples of LCM, 24 = 48
So, the correct answers are:
B) 24 and
D) 48
