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10-09-2020
Chemistry

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What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?

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kinsondols186 kinsondols186

10-09-2020

Answer:

178.67K

Explanation:

PV=nRT

T=PV/nR

= 1.072atm*20L/1.485mol*0.0821LatmK^-1

=178.67K

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