susannaking1863 susannaking1863

10-09-2020
Mathematics

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How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a misture that is 50% antifreeze? Use the she-step method

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samuelonum1 samuelonum1

15-09-2020

Answer:

210 gaL 60 % Antifreeze II

Step-by-step explanation:

In the problem, there are two types of antifreeze

antifreeze I and

antifreeze II

antifreeeze I 20 ----70 gal

Antifreeze II 60 ----- x gal

Total 50 ---------------- (70 + x ) gal

20*70+60*x=50(70+x)

1400+60x=3500+50x

60x-50x=3500-1400

10x=2100

x= 210

x=210 gaL 60 % Antifreeze II

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