Respuesta :

Answer:Let n = the smallest integer

Then the other integers are n+1, n+2, n+3 and n+4

Sum = n + n+1 + n+2 + n+3 + n+4 = 5n + 10 = 5(n + 2)

So the sum is always divisible by 5, for any value of n

Step-by-step explanation:

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