Respuesta :

jshe4926

Answer:

y[tex]\leq[/tex] -12 or y[tex]\geq[/tex] -4

  1. Subtract 6 from both sides 3|y+8|+6-6[tex]\geq[/tex]18-6
  2. Simplify 3|y+8|[tex]\geq[/tex]12
  3. Divide both sides by 3
  4. Simplify |y+8|[tex]\geq[/tex]4
  5. Apply absolute rule y+8[tex]\leq[/tex] -4 or y+8[tex]\geq[/tex]4
  6. Combined the interval y[tex]\leq[/tex] -12 or y[tex]\geq[/tex] -4

y[tex]\leq[/tex] -12 or y[tex]\geq[/tex] -4

:) Hope You Enjoy :)

They are both real numbers :)

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