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Data for CH3COOH(l) + C2H5OH(l) CH3COOC2H5(l) + H2O(l) balance were obtained at 100. The initial concentrations of the reagents are indicated in columns 1 and 2 of the table below and the CH3COOC2H5 concentrations in equilibrium are given in column 3. Calculate H2O and determine the value of KC

Data for CH3COOHl C2H5OHl CH3COOC2H5l H2Ol balance were obtained at 100 The initial concentrations of the reagents are indicated in columns 1 and 2 of the table class=

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MathPhys

Answer:

Kc = 3.94

Explanation:

CH₃COOH(g) + C₂H₅OH(g) → CH₃COOC₂H₅(g) + H₂O(g)

Liquids aren't included in the equilibrium constant, but at 100°C, all four compounds are a gas.  So the equilibrium equation is:

Kc = [CH₃COOC₂H₅] [H₂O] / ([CH₃COOH] [C₂H₅OH])

Set up an ICE table for each row and calculate the value of Kc.  Then average the results.  (See picture.)

Kc ≈ (3.919 + 4.012 + 3.902) / 3

Kc ≈ 3.94

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