bnickel bnickel
  • 10-11-2020
  • Mathematics
contestada

2log(base 5)^(x-3)-log(base 5)^8= log(base 5)^2

Respuesta :

Hrishii
Hrishii Hrishii
  • 10-11-2020

Answer:

x = 7

Step-by-step explanation:

[tex]2log_5(x-3)-log_58= log_52\\\\

2log_5(x-3) =log_52+log_58\\\\

2log_5(x-3) =log_5(2\times 8) \\\\

2log_5(x-3) =log_516\\\\

2log_5(x-3) =log_54^2 \\\\

2log_5(x-3) =2 log_54 \\\\

log_5(x-3) =log_54 \\\\

x - 3 = 4\\\\

x = 4+3\\\\

\huge \orange { \boxed{x = 7}}

[/tex]

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