Answer:
The required equation of line in point-slope form is:
[tex]y-6 = -7(x-3)[/tex]
Step-by-step explanation:
Given points are:
(x1,y1) = (3,6)
(x2,y2) = (5,-8)
The point-slope form of an equation is given by:
[tex]y-y_1 = m(x-x_1)[/tex]
Here m is slope of the line and (x1,y1) is a point on line
The slope is calculated using the formula:
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
Putting the values we get
[tex]m = \frac{-8-6}{5-3}\\m=\frac{-14}{2}\\m= -7[/tex]
Putting in the equation
[tex]y-y_1 = -7(x-x_1)[/tex]
Now we have to put a point in the equation, putting (3,6) in the equation
[tex]y-6 = -7(x-3)[/tex]
Hence,
The required equation of line in point-slope form is:
[tex]y-6 = -7(x-3)[/tex]
