contestada

A 2.00 L pocket of air at sea level has a pressure of 99.9 atm. What is the
pressure if the pocket of air rises and expands to 8.0 L? *
0.04 atm
O
400 atm
25 atm
52 atm​

Respuesta :

Stephen46

Answer:

The answer is 25 atm

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

From the question we have

[tex]P_2 = \frac{2 \times 99.9}{8} = \frac{199.8}{8} \\ = 24.975[/tex]

We have the final answer as

25 atm

Hope this helps you

Answer:

25 atm

Explanation:

Hope I helped

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