Answer:
I = 2.99 A
Explanation:
magnetic field, B = 0.96 T, length of wire, l = 2.7 m, mass of wire, m = 0.79 kg.
Since it is expected that the wire would vibrate or move in the magnetic field, from Newton's second law of motion;
F = mg
where F is the force on the wire, m is the mass of the wire and g is the acceleration due to gravity.
But,
F = BIL
⇒ BIL = mg
0.96 x I x 2.7 = 0.79 x 9.8
2.592I = 7.742
I = [tex]\frac{7.742}{2.592}[/tex]
= 2.9869
I = 2.99 A
The required minimum current is 2.99 A.
