Answer:
d) 0.8 mile
Step-by-step explanation:
Coordinate of object B = (6, 6)
Coordinate of object C = (1, 4)
Coordinate of the archaeologist = (6, 1)
✍️Distance between Object B (6, 6) and the archaeologist (6, 1):
Distance = |6 - 1| = 5 units = 5 miles
✍️Distance between Object C (1, 4) and the archaeologist (6, 1):
Using the distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex], we would have:
[tex] d = \sqrt{(6 - 1)^2 + (1 - 4)^2} [/tex]
[tex] d = \sqrt{(5)^2 + (-3)^2} [/tex]
[tex] d = \sqrt{25 + 9} [/tex]
[tex] d = \sqrt{34} = 5.8 units = 5.8 miles [/tex] (nearest tenth)
Comparing how far each object is from the archaeologist, object C is 0.8 mile (5.8 - 5 = 0.8) farther than object B.
