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PQ is formed by P(10,4 ) and Q(2,-8) of line k is the perpendicular bisector of PQ write a linear equation

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Answer:

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: ([tex]\frac{x_{1} + x_{2} }{2} \\[/tex], [tex]\frac{y_{1} + y_{2}}{2}[/tex])

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula: [tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = [tex]\frac{3}{2}[/tex]x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = [tex]\frac{3}{2}[/tex](6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

The linear equation formed from the  perpendicular bisector of PQ is y = -2/3 x + 2

The standard equation of a line is expressed as y = mx + b

m is the slope

b is the y-intercept

Given the coordinate points P(10,4 ) and Q(2,-8), find the slope of the line passing through the points.

m = -8-4/2-10

m = -12/-8

m = 3/2

The slope of the perpendicular bisector will be -2/3

Get the y-intercept.

Using the midpoint of the coordinates P(10,4 ) and Q(2,-8) and m = -2/3 into the formula y = mx + b

[tex]m = (\frac{10+2}{2},\frac{4-8}{2} )\\m=(6, -2)[/tex]

-2 = -2/3(6) + b

-2 = -4 + b

b = 2

Hence the linear equation formed from the  perpendicular bisector of PQ is y = -2/3 x + 2

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