What is the specific heat of a substance if 60.0 J are required to increase the temperature of 6 grams
by 11 degrees Celsius?

What is a likely identity of this substance?

Respuesta :

Using the specific heat capacity formula:

q = mc ∆ t
60.0 J = (6g)(x)(11*C)
x = 0.9 J/g*C

Aluminum