Respuesta :

Sry,i only the answer of that question no.1

(m)=1000kg

(u)=30m/s

(f)=5000n

(v)=0m/s

(a)=f/m

= 5000/1000

=5

Distance(s)=?

We know that,

V^2=u^2+2as

Or,0^2=30^2+2×5×s

Or,s=910m

So,the minium distance required to stop the car is 910m.

Hope,itwillhelpya!