Answer:
0.04 mol Ne
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Gas Laws
Combined Gas Law: PV = nRT
- P is pressure (in kPa)
- V is volume (in liters)
- n is amount of moles
- R is gas constant - [tex]\displaystyle 8.314 \frac{kPa \cdot L}{mol \cdot K}[/tex]
- T is temperature (in Kelvins)
Explanation:
Step 1: Define
P = 200 kPa
V = 0.50 L
T = 50°C
Step 2: Identify Conversions
Temperature Conversion: K = °C + 273.15
Step 3: Convert
- Substitute T [TC]: K = 50°C = 273.15
- Add: K = 323.15
Step 4: Find Moles
- Substitute [CBL]: [tex]\displaystyle (200 \ kPa)(0.50 \ L) = n(8.314 \frac{kPa \cdot L}{mol \cdot K} )(323.15 \ K)[/tex]
- Multiply: [tex]\displaystyle 100 \ kPa \cdot L = n(2686.67 \frac{kPa \cdot L}{mol})[/tex]
- Isolate n: [tex]\displaystyle 0.037221 \ mol = n_{Ne}[/tex]
- Rewrite: [tex]\displaystyle n_{Ne} = 0.037221 \ mol[/tex]
Step 5: Check
Follow sig fig rules and round. We are given 1 sig figs as our lowest.
0.037221 mol Ne ≈ 0.04 mol Ne
