Answer: Molarity of the given hydrochloric acid solution is 0.106 M.
Explanation:
Given: [tex]M_{1}[/tex] = 0.143 M, [tex]V_{1} = 20.5 mL[/tex]
[tex]M_{2}[/tex] = ? , [tex]V_{2} = 27.6mL[/tex]
Hence, molarity of the given hydrochloric acid solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
[tex]0.143 M \times 20.5 mL = M_{2} \times 27.6 mL[/tex]
[tex]M_{2} = \frac{0.143M \times 20.5 mL}{27.6 mL}[/tex]
= 0.106 M
Therefore, molarity of the given hydrochloric acid solution is 0.106 M.
