Answer:
14.94°C
Explanation:
Given parameters:
Mass of graphite = 0.33kg
Quantity of heat absorbed = 350J
Specific heat capacity of graphite = 710J/kg°C
Unknown:
Temperature change = ?
Solution:
To solve this problem, we use;
H = m c Ф
H is the quantity of heat
m is the mass
c is the specific heat capacity
Ф is the change in temperature
350 = 0.033 x 710 x Ф
Ф = 14.94°C
