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1. A 56.2 kg ball is loaded into a 1.27kg cannon. The cannon is at rest when it is ignited. Immediately after the impulse of the explosion, a photogate timer measures the cannon to recoil backwards a distance of 6.1 cm in 0.0218 seconds. Determine the post-explosion speed of the cannon and of the ball.

Respuesta :

Answer:

vc = v cannon

mc = m cannon

vb = v ball

mb = m ball

vc = d / t

= (6.1 cm) / (0.0218 s)

= 280 cm/s

mb x vb = -mc x vc

(negative as it is in the opposite direction)

(0.0562) x vb = - (1.27) x (-280)

vb = - (1.27) x  (-280) /  (0.0562)

= 6323.26 cm/s

ball = 63.2 m/s

cannon = 2.8 cm/s - recommend changing to m before calculations

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