The heat absorbed to raise temperature : Q = 31350 J
Further explanation
Given
m = mass = 150 g
Δt = Temperature difference : 50 °C
Required
Heat absorbed
Solution
Heat can be formulated
Q = m.c.Δt
The specific heat of water = c = 4.18 J/g °C
Input the value :
Q = 150 x 4.18 x 50
Q = 31350 J
